#include<stdio.h>
int main()
{
int x=0,y=1;
if(x=0)
{
printf("True\n");
}
else
{
printf("False\n");
}
return 0;
}
Solution
False
if(x=0) then x value is assigned to zero. now if(x=0) becomes if(0). The rule is if(n) becomes true when n is any positive or negative number except zero. so the condition is failed. so the else part is executed. The answer is false
if(x=0) then x value is assigned to zero. now if(x=0) becomes if(0). The rule is if(n) becomes true when n is any positive or negative number except zero. so the condition is failed. so the else part is executed. The answer is false
2.What is the output of the following program?
#include<stdio.h>
int main()
{
int x=1;
x=5+5*x++;
printf("x=%d\n",x);
return 0;
}
Solution
x=11
When Postfix(x++) operation is used with variable in expression then the expression is evaluated first with original value then the variable is incremented.
x=5+5*1=>x=5+5=>10
now x will be incremented by one.x=10+1=>x=11
When Postfix(x++) operation is used with variable in expression then the expression is evaluated first with original value then the variable is incremented.
x=5+5*1=>x=5+5=>10
now x will be incremented by one.x=10+1=>x=11
3.What is the output of the following program?
#include<stdio.h>
int main()
{
int x=1,y;
y=5+5*x++;
printf("x=%d\t y=%d\n",x,y);
return 0;
}
Solution
x=2 y=10
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